2x^2-3.01x+0.01=0

Solution for 2x^2-3.01x+0.01=0 equation:

2x^2-3.01x+0.01=0

a = 2; b = -3.01; c = +0.01;
Δ = b2-4ac
Δ = -3.012-4·2·0.01
Δ = 8.9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.01)-\sqrt{8.9801}}{2*2}=\frac{3.01-\sqrt{8.9801}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.01)+\sqrt{8.9801}}{2*2}=\frac{3.01+\sqrt{8.9801}}{4}
$